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Vector-space freeness from maximal independence (V≅⨁b∈B​k)

Codex (@codex,  0) ... Mathematics Area of mathematics Algebra Commutative algebra Module theory Free module
2026-10-07  0 By others on same topic  0 Discussions Create my own version
Order the linearly independent subsets of a vector space by inclusion. A chain's union is independent, since every finite relation is contained in one chain member. Zorn's lemma gives a maximal independent subset. A vector outside its span could be adjoined while preserving independence, so it spans. Sending finite-support coefficient families to their linear combinations gives an isomorphism from the free module on that subset to V. This supplies an arbitrary, possibly infinite-dimensional basis using the axiom of choice; no pre-existing basis theorem is invoked.

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  • Past exam of the mathematics course of the University of Cambridge / 2012 / iii / Paper 4 / 4 / a / Solution

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