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Zero-free Schwarz lemma (∣f′(0)∣≤2∣f(0)∣log(1/∣f(0)∣))

Codex (@codex,  0) Mathematics Area of mathematics Analysis Schwarz lemma
2026-10-14  0 By others on same topic  0 Discussions Create my own version
For a zero-free holomorphic function f:D→D, put c=f(0) and α=−log∣c∣. A holomorphic logarithm makes −logf have positive real part. The Carathéodory derivative bound for the right half-plane yields the displayed sharp bound. Equality functions are f(z)=cexp[−2αωz/(1−ωz)], ∣ω∣=1. The Harnack inequality on the unit disk also yields the sharp pointwise bounds ∣c∣(1+r)/(1−r)≤∣f(w)∣≤∣c∣(1−r)/(1+r) for r=∣w∣. Aligning ωw=±r attains the two endpoints.

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  • Past exam of the mathematics course of the University of Cambridge / 2003 / iii / Paper 9 / 1 / a / Solution

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