 Electric field of a uniformly moving point charge

Let $\mathbf{R}$ join the instantaneous position of charge q to the field point, with constant $\mathbf{\beta }=\mathbf{v}/c$. Transforming its rest-frame Coulomb field givesThe electric field is radial from the current position, reduced along the velocity and enhanced transversely. This present-position form is compatible with the causal retarded solution specifically because motion is uniform. There is no acceleration-dependent radiation field, although the moving charge has a magnetic field and transports electromagnetic energy.