 Input capacitance inferred from measured admittance

Input capacitance inferred from measured admittance is a parameter estimate from the quadrature component of a specified electrical port's response. In the parallel model of input capacitance, write its electrical admittance as $Y=G+i\omega C$ with the $e^{i\omega t}$ convention. A small sinusoidal excitation and simultaneous input-current measurement giveBoth amplitude ratio and relative wave phase matter. The differential versus common-mode terminals and operating point conditions must be specified, as in the manufacturer's input-path diagrams.^[ref]

For an original error calculation, suppose the amplitude ratio is exact but the measured current-to-voltage wave phase has offset $\delta$. Then $Y_{\mathrm{meas}}=Y{e}^{i\delta }$ andThe phase calibration error in an admittance-based capacitance estimate can therefore mix a conductance term into the small capacitive estimate. For small $\delta$, the leading error is $(G/\omega )\delta$, not a fixed percentage of $C$.

Choose $G=10\mu \mathrm{S}$, $C=20\mathrm{pF}$, and $f=10\mathrm{kHz}$. The true susceptance is only $\omega C\approx 1.257\mu \mathrm{S}$. A one-degree wave phase offset yields $\hat{C}\approx 22.775\mathrm{pF}$, an error of about $13.9\%$, despite perfect amplitude readings. These are chosen port-model values, not measured device specifications.

A useful measurement repeats the estimate over frequency and excitation amplitude. A nearly constant fitted $C$ and a residual consistent with $G+i\omega C$ support the assumed model; they do not prove that all parasitic effects were removed. A known fixture admittance adds to a parallel port and must be subtracted or retained in the model. At very small susceptance, uncertainty in the relative wave phase can dominate, so a high DC input impedance alone is not evidence for a precise capacitance measurement.