 Local finiteness does not imply finite intensity

Here is an explicit example even within simple point processes. Let $K$ be a positive integer with probability mass function $\mathbb{P}(K=k)=1/[k(k+1)]$. The telescoping series sums to one, $K$ is finite almost surely, but $\mathbb{E}[K]={\sum }_{k\ge 1}1/(k+1)=\infty$. Conditional on $K$, sample $K$ independent points with the uniform distribution on $(0,1)$. The resulting point process has finitely many distinct points almost surely, while $\mu ((0,1))=\infty$. Thus finite counts in each realization and finite mean counts are separate requirements; local finiteness of the intensity measure is an integrability assumption.