 Solution

The central limitation is that a Hartree-Fock electron gas includes exchange but omits the correlation energy that is not representable by one determinant. Opposite-spin electrons can lower their repulsion by avoiding one another in a correlated unpolarized state. Hartree-Fock misses that avoidance while retaining the exchange advantage of aligned spins, so it need not place a magnetic instability at a reliable interaction strength. The relevant energy differences between competing spin states can be much smaller than their total energies. Correlation calculations of the electron gas explicitly address this competition.^[ref]

There are further model restrictions. A constant contact coupling discards the momentum dependence of the Coulomb interaction and the resulting nontrivial screening. Real materials have a lattice, band structure and material-dependent effective interactions. Spatial magnetic textures or other competing states are excluded by a comparison restricted to uniform Fermi spheres. Even before those changes, part c's two endpoints do not find the continuous polarization onset.

The symbol $r_s$ also needs care. Here it is an energy ratio proportional to $\gamma n^{1/3}$. The usual Dimensionless Wigner-Seitz radius of a three-dimensional Coulomb electron gas is $r_s^{\mathrm{WS}}=[3/(4\pi n){]}^{1/3}/a_B$, proportional to $n^{-1/3}$. They are not the same density parameter. A quoted experimental value of the latter cannot be compared numerically to $1.175$ without a model-specific mapping. The contact interaction, missing correlations, restricted variational class and parameter convention prevent the number $1.175$ from being a quantitative experimental prediction. The paper supplies no particular experimental threshold, so none is invented here.