Solution

ID: past-exam-of-the-algebra-analysis-and-differential-equations-1-course-of-the-university-of-oxford/2005/4/iv/solution

If a holomorphic function on the punctured complex plane satisfied , the chain rule would give , hence . This contradicts the previous part. Therefore there is no global holomorphic logarithm on the punctured plane. A branch of the complex logarithm requires a suitable smaller domain.

New to topics? Read the docs here!