 Solution

Each isomer has one favourable anomeric interaction. A has the favourable axial exocyclic oxygen in the upper-ring chair; B has it in the lower-ring chair. The NMR-constrained conformations therefore do not provide a doubly anomeric versus non-anomeric comparison.

Both can keep important carbon substituents equatorial and each obtains one anomeric stabilization. Appreciable amounts of both are therefore a reasonable prediction, rather than a strong preference based solely on counting anomeric interactions. The environments of the two ring oxygens are not identical, so this argument does not determine an exact one-to-one equilibrium ratio; quantitative preference would require further energetic information.