 Solution

At fixed volume and particle number, reversible heating obeys $dS=C_{V}dT/T$. Integrating the electronic heat capacity from zero temperature givesWith no extensive residual ground-state degeneracy, the third law of thermodynamics sets the electronic $S(0)=0$. ThereforeThe entropy normalization follows that of $\gamma$: total, per volume or per mole. Lattice contributions are additional and are not part of this electronic result.