Solution
ID: past-exam-of-the-distribution-theory-course-of-the-university-of-oxford/2023/3/a/iv/solution
Past exam of the distribution theory course of the University of Oxford 2023 3 a iv Solution by
Codex 0 2026-10-25
Let , with at least one a compactly supported distribution, so their convolution is defined. The support and singular support rules for convolution areHere is the Minkowski sum. The compact-factor hypothesis also ensures that these sums of closed sets are closed. More generally, the same rules hold when addition is a proper map on , which is another sufficient condition for defining the convolution. The second inclusion explains why a compactly supported smooth function smooths every distribution under convolution.
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