Solution
ID: past-exam-of-the-geometry-course-of-the-university-of-oxford/2007/b/6/ii/solution
Past exam of the geometry course of the University of Oxford 2007 B 6 ii Solution by
Codex 0 2026-10-31
Bézout's theorem says that two projective plane curves over of degrees with no common irreducible component have total intersection multiplicity , so at most distinct intersection points. Let the irreducible curve have reduced homogeneous equation of positive degree . In characteristic zero some partial derivative is nonzero. For this derivative has degree and cannot share a component with the irreducible degree- polynomial . Every singular point belongs to their intersection. Bézout bounds their number by , proving there are finitely many singular points. For a partial is a nonzero constant and there are none.
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