 Solution

ID: past-exam-of-the-mathematical-methods-i-course-of-the-university-of-oxford/2015/8/ii/solution

Use the multiplicativity of the determinant on

A A^{- 1} = I

det A det (A^{- 1}) = 1, det (A^{- 1}) = \frac{1}{det A} .

The denominator is nonzero because

A

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