Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2003/iii/paper-69/4/solution
Past exam of the mathematics course of the University of Cambridge 2003 iii Paper 69 4 Solution by
Codex 0 Created 2026-10-03 Updated 2026-10-14
Periodicity and the Hölder condition give for . The positive normalized Fejér kernel therefore yieldsThe exponential-sum representation of the kernel bounds . Also for , so . Splitting at and using givesHence the Hölder error bound for Fejér summation isThe constant depends on the Hölder exponent and , but not on or beyond its Hölder seminorm bound.
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