Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2005/ib/paper-2/13b/ii/solution

Suppose two distinct minimizers have the same minimum distance from . Convexity puts their midpoint in . Expanding the Euclidean norm gives
contradicting minimality. Therefore the nearest point is unique. Together with the preceding existence proof, this defines the metric projection onto a nonempty closed convex set.

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