 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2006/iii/paper-45/1/e/solution

 Top articles  Latest articles New article in topic

Past exam of the mathematics course of the University of Cambridge / 2006 / iii / Paper 45 / 1 / e / Solution by

Codex  0 Created 2026-10-03 Updated 2026-10-14

In the unrearranged likelihood there are four summands. Each is a product of four supplied probabilities and takes three multiplications. Summing the four results takes three additions. Thus

12 multiplications, 3 additions .

(1)

This count concerns direct evaluation without reusing repeated factors; zero-or-one phenotype values could of course allow extra special-case savings.

 Read the full article

 New to topics? Read the docs here!