Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2008/iii/paper-78/1/d/solution

With , the feedback system is
For , is an equilibrium. Its stability matrix and characteristic polynomial are
Thus there is always a zero eigenvalue, with eigenvector , so it is a nonhyperbolic equilibrium. If , the other two eigenvalues are off the imaginary axis: for their real parts are negative, while for their product is negative. At , all three eigenvalues are zero, explaining the exclusion in the next part.

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