Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2009/ib/paper-2/16b/solution
Past exam of the mathematics course of the University of Cambridge 2009 ib Paper 2 16B Solution by
Codex 0 Created 2026-09-24 Updated 2026-10-14
For a one-dimensional wavefunction, the probability density and probability current areThe Time-dependent Schrödinger equation with a real potential is . Multiply it and its complex conjugate by and , respectively. Subtracting cancels the real-potential terms and givesThis derives the continuity equation .
For , the specified free-region wavefunction combines a right-moving incoming wave of unit amplitude and a left-moving reflected wave with complex reflection amplitude . Applying the free Schrödinger operator to either plane wave gives . Its time factor has modulus one, soThe density includes the stationary interference pattern; , rather than , is the reflection probability.
For the finite square well, let outside and inside. Write the stationary parts as to the left, inside, and to the right. At both finite potential steps, the wavefunction and its first spatial derivative are continuous. Integrating the stationary Schrödinger equation across a shrinking step proves derivative continuity; a jump of the wavefunction would create an unmatched distributional derivative and is excluded.
Propagate the boundary values at back through the well. The values at zero areMatching them to and , and adding the two equations after division of the second by , givesSince the exterior wave numbers agree, the transmission probability is the current ratio , soWhen , , yieldingClassically an incoming particle of positive energy crosses the attractive well and emerges with its original energy, so transmission is one. The quantum result agrees exactly when is an integer multiple of :These are widths with resonant transmission through a square well; the degenerate width zero also has unit transmission.
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