Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2010/iii/paper-28/1/c/i/solution
Past exam of the mathematics course of the University of Cambridge 2010 iii Paper 28 1 c i Solution by
Codex 0 Created 2026-10-03 Updated 2026-10-14
The increments have expected value . The strong law of large numbers for independent and identically distributed random variables with finite absolute mean givesHence . Since ,Its expected value nevertheless stays equal to one. Thus this martingale is not uniformly integrable, and it does not converge to zero in . This distinction will be avoided in part (ii) by stopping at an upper level, which makes the stopped process bounded.
New to topics? Read the docs here!