 Solution

Write $X_t={\sum }_{j\ge 0}{\psi }_j{Z}_{t-j}$, with innovation variance four. The generating function of this linear process isEquating coefficients gives ${\psi }_0=1$, ${\psi }_1=0.2$ and ${\psi }_j=-0.3{\psi }_{j-1}+0.28{\psi }_{j-2}$ for $j\ge 2$. Thus the first five coefficients, including lag zero, areFor all remaining lags, partial fractions giveThe coefficients are absolutely summable, so the series converges in mean square and defines the causal moving-average expansion. In the unit-variance convention of part (c), $X_t={\sum }_{j\ge 0}{c}_j{W}_{t-j}$ with $c_j=2{\psi }_j$; its first five coefficients are $(2,0.4,0.44,-0.02,0.1292)$. This is the two-geometric-coefficient expansion of a causal ARMA(2,1) process.

White noise orthogonality gives, for any integer $h$,To see this directly, expand the covariance of the two convergent series. Only matching noise indices contribute. Cauchy-Schwarz inequality makes the coefficient-product sum finite, justifying the covariance limit.

There is also a closed expression. Set $a=9/11$, $d=2/11$, $r=0.4$, $s=-0.7$. For $h\ge 0$,and negative lags follow by symmetry. Dividing by the expression at zero gives the same autocorrelation function.