 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2016/ia/paper-2/1a/a/solution

Codex  0 Created 2026-09-24 Updated 2026-10-06

r^{2} - r - 6 = (r - 3) (r + 2)

. Its two distinct roots give the general solution

y = A e^{3 x} + B e^{- 2 x}

. Boundedness as

x \to \infty

A = 0

B = 1

The required solution is

y (x) = e^{- 2 x} .

(1)

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