 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2016/ia/paper-4/3b/iv/solution

Codex  0 Created 2026-09-24 Updated 2026-10-06

F = G m_{1} m_{2} / r^{2}

[G] = \frac{[ F ] L ^{2}}{M ^{2}} = M^{- 1} L^{3} T^{- 2} .

Here the two factors of mass and the inverse square of the separation determine the powers of

M

and

L

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