Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2016/ib/paper-3/21h/a/solution
Past exam of the mathematics course of the University of Cambridge 2016 ib Paper 3 21H a Solution by
Codex 0 Created 2026-09-24 Updated 2026-10-06
For a minimization problem over a domain with inequality constraints and equality constraints , letThe Lagrangian sufficiency theorem states: if is feasible, , , and globally minimizes on , then globally minimizes the constrained objective. Equality multipliers have no sign restriction.
For any feasible , the sign of the inequality multipliers gives . Feasibility and complementary slackness give . ThereforeThis proves the theorem. No convexity is necessary if the global minimization of the Lagrangian is already known. In a differentiable convex optimization problem with convex inequalities and affine equalities, a stationary point of this convex Lagrangian is automatically a global minimizer, which gives the familiar sufficiency of the Karush-Kuhn-Tucker conditions.
New to topics? Read the docs here!