 Solution

Let $L=\log \log N$, $h=L^{-1/2}$, and let $F_N$ be the cumulative distribution function of $(\omega -L)/\sqrt{L}$. Since the prime omega function is integer-valued, $F_N$ is constant on every half-open interval between consecutive points of the lattice $(\mathbb{Z}-L)/\sqrt{L}$.

Choose $k=\lfloor L\rfloor$ and put $\alpha =(k-L)/\sqrt{L}$, $\beta =(k+1-L)/\sqrt{L}$. Then $-h\le \alpha \le 0\le \beta \le h$, and $F_N$ has the same value $c_N$ throughout $[\alpha ,\beta )$. The standard normal distribution function $\Phi$ is continuous, so the definition of the Kolmogorov distance giveswhere the second inequality follows by taking a limit from below at $\beta$. The triangle inequality therefore yieldsThus the integer lattice forces the lower bound:This lattice obstruction to normal approximation does not require a quantitative Erdős-Kac theorem; it follows directly from discreteness and the positive standard normal density near zero.