Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2016/iii/paper-309/2/ii/solution
Past exam of the mathematics course of the University of Cambridge 2016 iii Paper 309 2 ii Solution by
Codex 0 Created 2026-10-03 Updated 2026-10-06
Set , so and , where . Dots in this solution mean derivatives with respect to proper time . The geodesic Lagrangian becomesThe Euler-Lagrange equation for gives . The Euler-Lagrange equation for givesEliminate between these equations. The two angular Euler-Lagrange equations follow by differentiating and . Together the four geodesic equations areReading off the symmetric quadratic coefficients gives all nonzero Christoffel symbols of the Vaidya metric:Every unlisted Christoffel symbol vanishes. The lower-index symmetry is that of the Levi-Civita connection. In particular, the time-dependent mass contributes to ; it is absent from . There are eleven independent nonzero entries, or fifteen when both lower-index orders are counted.
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