Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2016/iii/paper-336/2/a/ii/solution
Past exam of the mathematics course of the University of Cambridge 2016 iii Paper 336 2 a ii Solution by
Codex 0 Created 2026-10-03 Updated 2026-10-06
Write , and . The first correction in the inner expansion satisfies . Direct differentiation verifies that is a particular solution. Adding the constant and error function homogeneous solutions gives .
The left boundary condition forces . Re-expanding the outer expansion at givesTherefore , with no constant term in its large- overlap. Since and , this sets . Thus the required half-order correction isIt vanishes at zero and has the correct linear overlap. Keeping this term is essential even though the outer solution has no correction of that order.
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