Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2017/ib/paper-3/6d/a/solution

For the boundary constraint , the Lagrange multiplier equations for are
Neither coordinate can vanish at a stationary point. Substitution gives . For , and ; for , and . The constraint circle is compact, its gradient is nowhere zero, and every extremum must occur among these stationary points. Thus
The paired signs in each expression are linked. The inequality also confirms the global values.

New to topics? Read the docs here!