Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2017/iii/paper-339/2/a/solution

Split the sign vector as . Multiplication of the two off-diagonal blocks gives
because the two terms are the same real scalar. The map is a bijection between the feasible sign choices. Therefore
This is the symmetric lifting of bipartite binary quadratic optimization to binary quadratic optimization. The factor is necessary: otherwise the two blocks would double the objective. No positive semidefiniteness of is assumed; generally its off-diagonal structure makes its quadratic form indefinite.

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