Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2019/iii/paper-348/1/b/solution

Given any admissible transport map , form its graph transport plan
For Borel sets and , the definition of a pushforward measure gives
Hence . Integration against a pushforward measure also gives
The Kantorovich optimal transport problem therefore has at least all the competitors of the Monge optimal transport problem, with exactly the same costs. Consequently
If there is no admissible transport map, the left side is by the convention , so the conclusion still holds. No existence of an optimizer is needed.

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