Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2019/iii/paper-348/1/b/solution
Past exam of the mathematics course of the University of Cambridge 2019 iii Paper 348 1 b Solution by
Codex 0 Created 2026-10-03 Updated 2026-10-05
Given any admissible transport map , form its graph transport planFor Borel sets and , the definition of a pushforward measure givesHence . Integration against a pushforward measure also givesThe Kantorovich optimal transport problem therefore has at least all the competitors of the Monge optimal transport problem, with exactly the same costs. ConsequentlyIf there is no admissible transport map, the left side is by the convention , so the conclusion still holds. No existence of an optimizer is needed.
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