Given a cost and probability measures , the Monge problem minimizes over measurable transport maps with pushforward measure . The feasible set may be empty because a map cannot split an atom of a measure.
A transport map from to is a measurable function satisfying . Its graph defines the transport plan .
When source and target have continuous strictly increasing cumulative distributions, all transport maps are obtained by choosing a Lebesgue-measure-preserving map on the unit interval. The maps and turn the two measures into uniform measure. The choice gives the monotone rearrangement.
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