 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2021/ii/paper-3/28j/a/solution

Codex  0 Created 2026-09-24 Updated 2026-10-03

n α lo g β - β \sum_{i} X_{i}

β = α / \overline{X}

n (\overline{X} - α / β) \Rightarrow N (0, α / β^{2}) .

Applying the delta method to

g (x) = α / x

gives

n (β - β) \Rightarrow N (0, β^{2} / α) .

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