Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2021/iii/paper-205/4/a/solution

Regard each centered random variable as a vector in the Hilbert space . Then
so is the Gaussian kernel on the finite subset of that Hilbert space. More explicitly,
Every power of the inner-product kernel is positive semidefinite, and the closure property of positive-semidefinite kernels under nonnegative sums, pointwise limits, and multiplication by one-variable factors proves that is positive definite.

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