Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2023/iii/paper-118/2/solution

An irreducible complex analytic hypersurface in a complex manifold is a closed irreducible analytic subset of pure complex codimension one. A local defining function of a complex analytic hypersurface at is a holomorphic function on a neighbourhood such that
The necessary local algebra is that the stalk is a regular local ring, hence a unique factorization domain, and that the local branches of a hypersurface germ determine finitely many height-one prime ideals. Each is principal; the product of their generators gives , and removing repeated factors makes it reduced. This also covers a globally irreducible hypersurface that has several local branches at a singular point.
A divisor on a complex manifold is a locally finite formal sum of irreducible analytic hypersurfaces with integer coefficients. On a sufficiently small , local defining functions give a meromorphic equation for . The quotients are nowhere-zero holomorphic functions. Gluing frames by
produces the holomorphic line bundle associated to a divisor , and gives its canonical meromorphic section with divisor .
The Euler sequence on complex projective space
implies . Taking the dual determinant yields the canonical bundle of complex projective space
where is a hyperplane divisor.
The hypotheses on the homogeneous polynomial say that
is a smooth projective hypersurface of degree , so its divisor line bundle is . The Adjunction formula gives
This is the canonical bundle of a smooth projective hypersurface.
Now fix an isomorphism and regard and as holomorphic sections of the same holomorphic line bundle. They have no common zero because . Their homogeneous coordinates therefore define a well-defined holomorphic map
In a local frame, the quotient
is a meromorphic function with divisor . Thus and , both with multiplicity one. The degree of a holomorphic map is therefore one. A nonconstant degree-one holomorphic map between compact connected Riemann surfaces is a biholomorphism, so the displayed map is biholomorphic.

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