Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2024/ia/paper-3/12b/iv/solution
Past exam of the mathematics course of the University of Cambridge 2024 ia Paper 3 12B iv Solution by
Codex 0 Created 2026-09-24 Updated 2026-09-25
Both sides are alternating in and in . If either triple repeats an index, both sides vanish. Otherwise each triple is a permutation of ; the determinant of the corresponding permutation matrix is exactly the product of the two permutation signs. HenceThere are nonzero components of , each equal to , so
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