 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2025/ia/paper-4/10b/a/solution

Codex  0 Created 2026-09-24 Updated 2026-10-03

v^{2} /2

and

l = b v

, so

e = 1 + \frac{b ^{2} v ^{4}}{k ^{2}} .

The angle through which the velocity is deflected between the incoming and outgoing asymptotes is

χ = 2 tan^{- 1} (\frac{k}{b v ^{2}}) .

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