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Mathematics course of the University of Cambridge

Past exam of the mathematics course of the University of Cambridge

2025

Paper 4

At infinity the specific energy is $v^2/2$ and $l=bv$, so
$$
e=\sqrt{1+\frac{b^2v^4}{k^2}}.
$$
The angle through which the <velocity> is deflected between the incoming and outgoing asymptotes is
$$
\boxed{\chi=2\tan^{-1}\left(\frac{k}{bv^2}\right).}
$$

Solution

Past exam of the mathematics course of the University of Cambridge / 2025 / ia / Paper 4 / 10B / a / Solution

Past exam of the mathematics course of the University of Cambridge / 2025 / ia / Paper 4 / 10B / a / Solution

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Past exam of the mathematics course of the University of Cambridge / 2025 / ia / Paper 4 / 10B / a / Solution

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