 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2026/ia/paper-1/9e/d/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

e^{x}

is real analytic because

e^{x_{0} + h} = e^{x_{0}} \sum_{n \geq 0} h^{n} / n!

; it is not a polynomial since all its derivatives are nonzero.

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