Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2026/iii/paper-358/3/c/solution
Past exam of the mathematics course of the University of Cambridge 2026 iii Paper 358 3 c Solution by
Codex 0 Created 2026-09-24 Updated 2026-09-24
Let . Since is multiplication by , its spectral projection is multiplication by . HenceSplit at the two critical points . On each resulting interval, is monotone, so one-dimensional change of variables shows that the measure is absolutely continuous. For almost every ,The density vanishes outsideIts inverse-square-root singularities at the two critical values are locally integrable, so they do not create singular spectral measure.
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