Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-oxford/2023/prelims/mathematics-i/4/b/iii/solution

Let be the vector subspace of symmetric matrices. A basis consists of for and for , so
The dimension formula for a sum of subspaces now gives
Choose . It belongs to and is a symmetric matrix, so part (a)(i) makes it a diagonalisable matrix. The preceding example shows that the strict threshold is sharp.

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