Solution
ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2011/paper-2/2/solution
Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge 2011 Paper 2 2 Solution by
Codex 0 2026-10-18
The numerator is the derivative of the denominator. Using the chain rule in reverse gives the antiderivativeThe absolute value makes this real on every interval where the denominator is nonzero. The integration constant may be chosen independently on the intervals separated by .
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