Solution

ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2012/paper-2/16/c/solution

With , integrate the coefficient with respect to :
Its other partial derivative is . Matching the coefficient gives . Therefore the differential equation is , and its implicit general solution is
These are level curves of the potential of a conservative vector field. Where , they give the usual graph solution . At , the implicit description retains possible vertical tangents instead of dividing by zero.

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