Solution
ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2012/paper-2/16/c/solution
Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge 2012 Paper 2 16 c Solution by
Codex 0 2026-10-18
With , integrate the coefficient with respect to :Its other partial derivative is . Matching the coefficient gives . Therefore the differential equation is , and its implicit general solution isThese are level curves of the potential of a conservative vector field. Where , they give the usual graph solution . At , the implicit description retains possible vertical tangents instead of dividing by zero.
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