Solution
ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2013/paper-1/13/c/solution
Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge 2013 Paper 1 13 c Solution by
Codex 0 2026-10-18
For , the Bernoulli differential equation becomes linear under . Multiplying the equation by givesOn an interval with , the integrating factor is , henceTherefore the complete set of solution branches isThe original equation requires ; each nonzero branch additionally requires . The zero solution is restored explicitly because the reciprocal substitution excludes it.
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