Solution

ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2013/paper-1/13/c/solution

For , the Bernoulli differential equation becomes linear under . Multiplying the equation by gives
On an interval with , the integrating factor is , hence
Therefore the complete set of solution branches is
The original equation requires ; each nonzero branch additionally requires . The zero solution is restored explicitly because the reciprocal substitution excludes it.

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