 Solution

ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2015/paper-1/9/b/solution

1/ 6

. The required equation is

y - 1 = \frac{1}{6} (x - \frac{6}{2}), equivalently y = \frac{x}{6} + \frac{1}{2} .

The normal direction also agrees with the gradient

(4 x, 2 y)

of the defining level function.

 New to topics? Read the docs here!