Solution
ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2016/paper-1/17/a/ii/solution
Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge 2016 Paper 1 17 a ii Solution by
Codex 0 2026-10-18
After integrations, the general solution is an arbitrary polynomial of degree at most :Conversely, every such polynomial has zero th derivative. The free coefficients span the full solution space on a connected interval.
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