Solution
ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2016/paper-2/17/b/ii/solution
Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge 2016 Paper 2 17 b ii Solution by
Codex 0 2026-10-18
The homogeneous equation is the dot product condition . A suitable vector field is thereforeWhere nonzero, it is tangent to the level curves of and perpendicular to its gradient. At the origin this vector vanishes, so no direction is defined there.
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