 Solution

The characteristic polynomial of $A$ isIts distinct eigenvalues are $3$ and $-3$. For $3$, the eigenvector relation gives $y=-2x$, so choose $(1,-2{)}^T$. For $-3$, it gives $x=-2y$, so choose $(2,-1{)}^T$. Put these independent eigenvectors into columns:Then $AB=BC$ column by column. Also $\det B=3\ne 0$, so this choice supplies the diagonalization of a matrix $B^{-1}AB=C$. Scaling columns or interchanging their order gives other valid choices, with the matching order in $C$.