 Solution

ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2024/paper-1/13/a/i/solution

1 = 4 + \frac{1}{3} + C, C = - \frac{10}{3} .

Therefore the solution of this initial value problem is

y (x) = \frac{3 x}{x ^{4} - 10 x + 12} .

The formula is used on the interval containing

x = 1

where the original ordinary differential equation and the displayed expression are defined.

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