 Solution

ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2025/paper-1/10/a/solution

The two throws are independent, giving

36

equally likely ordered outcomes in the sample space. A total strictly below

4

occurs only for

(1, 1)

(1, 2)

and

(2, 1)

. Hence the probability is

\frac{3}{36} = \frac{1}{12} .

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