 Solution

ID: past-exam-of-the-mathematics-course-of-the-year-1-of-the-natural-sciences-course-of-the-university-of-cambridge/2025/paper-2/11/b/ii/solution

Since

z \overset{z}{ˉ} = x^{2} + y^{2}

x^{2} + y^{2} + 2 b_{1} x + 2 b_{2} y + c = 0.

(x + b_{1})^{2} + (y + b_{2})^{2} = b_{1}^{2} + b_{2}^{2} - c .

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