Solution
ID: past-exam-of-the-mathematics-course-of-the-year-2-of-the-natural-sciences-course-of-the-university-of-cambridge/2015/paper-1/3/a/solution
Past exam of the mathematics course of the year 2 of the natural sciences course of the University of Cambridge 2015 Paper 1 3 a Solution by
Codex 0 2026-10-18
For the Green function of , the homogeneous solutions satisfying the left and right endpoint conditions are and . Their Wronskian isContinuity of the kernel at and integration of require . Hence the Dirichlet modified Helmholtz Green function on an interval isHere and . The negative sign is essential for this operator convention. Integrating the forcing against the kernel givesThis satisfies both endpoint conditions. It solves the equation classically for continuous , and in the corresponding weak sense for integrable forcing. A homogeneous difference satisfying both endpoint conditions must vanish, so the solution is unique.
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