Solution
ID: past-exam-of-the-metric-spaces-and-complex-analysis-course-of-the-university-of-oxford/2015/2/d/solution
Past exam of the metric spaces and complex analysis course of the University of Oxford 2015 2 d Solution by
Codex 0 2026-10-31
Define on the sphere. It is continuous and satisfies . If at a chosen point, we are done. Otherwise choose a unit vector perpendicular to and follow the half great circleThe Pythagorean theorem shows that lies on the sphere, and its endpoints are . The continuous function has opposite signs at the endpoints. The Intermediate value theorem therefore gives a zero , soThis is a scalar equal-value assertion for an antipodal pair; it uses only a path and the Intermediate value theorem.
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